Finding all real roots of x^4-3x^3-5x^2+13x+6=0 ?

Hello from MrBillDoesMath!

3, -2,    1 +\- sqrt(2)

Discussion:

By the "rational root theorem" the roots of the given polynomial are factors of the constant term 6. These factors are  +\-1, +\-2, +\-3, or +\-6). Trial and error showed that  -2 and 3 were root so

x^4-3x^3-5x^2+13x+6 =

(x-3)(x+2) (x^2 -2x - 1)

Next we solve for the roots of the quadratic using the quadratic equation.

Regards,  

MrB

P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!

step-by-step explanation:

. your answer will contain x - and y -terms. (1 point) x ( ¿¿ 2 − 7 ) 2 +( y 2 − 9 ) 2 √ ¿ 12. what is the distance from the directrix (the crocodile river) to the point ( x , y )? write this equation. your answer will contain a y -term.