Which system of equations has a solution of approximately (1.8,-0.9) a. 6x-5y=15 and x+2y =0 b. 4x+5y=8 and 6x-5y=15 c. x-2y=4 and 4x+5y=8 d.6x-5y=15 and x-2y=4

Solve the equation systems or set the values x = 1.8 and y = -0.9 on the equation and check the equality.

A.

6x - 5y = 15

L = 6(1.8) - 5(-0.9) = 10.8 + 4.5 = 15.3

R = 15

L ≈ R

x + 2y = 0

L = 1.8 + 2(-0.9) = 1.8 - 1.8 = 0

L = R

B.

4x + 5y = 8

L = 4(1.8) + 5(-0.9) = 7.2 - 4.5 = 2.7

R = 8

L ≠ R

C.

x - 2y = 4

L = 1.8 - 2(-0.9) = 1.8 + 1.8 = 3.6

R = 4

L ≈ R

4x + 5y = 8

L = 4(1.8) + 5(-0.9) = 7.2 - 4.5 = 2.7

R = 8

L ≠ R

D.

6x - 5y = 15

L = 6(1.8) - 5(-0.9) = 10.8 + 4.5 = 15.3

R = 15

L ≈ R

x - 2y = 4

L = 1.8 - 2(-0.9) = 1.8 + 1.8 = 3.6

R = 4

L ≈ R

We have two probability solutions: A and D.

But I think, Your answer is A.

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

answer: i guess 5 units?

step-by-step explanation: