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Mathematics, 27.06.2019 14:30 dnjames01

The work of a student to solve the equation 4(2x βˆ’ 4) = 8 + 2x + 8 is shown below: step 1: 4(2x βˆ’ 4) = 8 + 2x + 8 step 2: 6x βˆ’ 8 = 16 + 2x step 3: 6x βˆ’ 2x = 16 + 8 step 4: 4x = 24 step 5: x = 6 in which step did the student first make an error and what is the correct step? step 2; 8x βˆ’ 4 = 2(6 + x + 6) step 2; 8x βˆ’ 16 = 16 + 2x step 3; 6x βˆ’ 2x = 16 βˆ’ 8 step 3; 6x + 2x = 16 + 8

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