The graph shows the function f(x) = |x – h| + k. what is the value of h? h = –3.5 h = –1.5 h = 1.5 h = 3.5

h = –1.5

Step-by-step explanation:

we know that

In the function  

The point (h,k) is the vertex of the function

where

h is the x-coordinate of the vertex

k is the y-coordinate of the vertex

In this problem the vertex is the point (-1.5,-3.5)

therefore

h=-1.5

the function  is

see the graph in the attached figure

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

10 you would take 50/ .2

step-by-step explanation: