Chloe charged for admission to her play on three different nights. each night, a different number of people were in attendance, but remarkably, chloe collected $541 each night. if the admission charges for each child and each adult were $9 and $17, respectively, how many people in total came to the three showings?

1st Play 45 people; 2nd Play 37 people; 3rd Play 53 people

Step-by-step explanation:

Admission prices were: $9 per child & $17 per adult.

It is only matter of playing with the numbers until you get the number you want. In this case, the number all plays have in common is $541 which represents the amount she collected for attendance.

1st Play 28 children ($252) + 17 adults ($289) = $541 and 45 people

2nd Play 11 children ($99) + 26 adults ($442) = $541 and 37 people

3rd Play 45 children ($405) + 8 adults ($136) = $541 and 53 people

This way, each night the number of people in attendance was different but the amount collected in each play was $541.

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

12/11c

or

12

c

11