What is the solution set to the following system x+y=5 x^2+y^2=25 a (0, -5) (-5,0) b (0,5) (-5,0) c (0,-5) (5, 0) d (0, 5) (5,0)

D (0, 5), (5, 0)

Anything with -5 and 0 will not satisfy x+y=5. This eliminates the first three choices.

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It is easiest to check the offered answers. You can also solve this graphically, or by solving the simultaneous equations.

You can, for example, square the first equation and subtract the second:

... (x+y)² -(x²+y²) = 5² -25

... 2xy = 0

This will be true for x=0 or for y=0, so (0, 5) and (5, 0) are solutions to the pair of equations.

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.

the one that has a slope of 1/2 and is positive.

step-by-step explanation: 2 buckets 1 trip ; 4 buckets 2 trips and so on.