Suppose a normal distribution has a mean of 98 and a standard deviation of 6. what is p(x< or = to 110)

97.8%

Step-by-step explanation:

110 is 2 standard deviations above the mean (6+6 = 12)

12+98 = 110

Looking at the standard deviation curve

P(x< or = to 110)  = 1 - P(x>110)

We can find the probability that x>100 by adding  anything above 2 standard deviations above the curve.

P(x>110) = 2.1+.1 = 2.2%

P(x< or = to 110)  = 1 - P(x>110)

                                = 1- 2.2%

                                = 1- .022

                                  = .978

                               = 97.8 %

answer: check all that apply, where the options?

step-by-step explanation: