If william has 5 different shirts and 7 different pairs of pants, how many different combinations could he wear?

35

Step-by-step explanation:

We are given that William has 5 different shirts and 7 different pairs of pants.

It is required to find out the possible combinations of shirts and pants that William could wear.

Let us assume that, William wears only one shirt and one pant at a time.

Therefore,

The total number of possible combinations = 5*7 = 35.

Hence, William can wear total 35 combinations.

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !