Astandard deck of 52 cards contains 13 cards with hearts, 13 with diamonds, 13 with clubs, and 13 with spades. how many 7-card hands are possible with 2 hearts, 2 diamonds, 2 clubs, and 1 spade? assume that the order of the cards does not matter, and use the formula for combinations to find your answer.

combinations.

Step-by-step explanation:

Given : A standard deck of 52 cards contains 13 cards with hearts, 13 with diamonds, 13 with clubs, and 13 with spades.

To find : The combination of 7-cards with 2 hearts, 2 diamonds, 2 clubs, and 1 spade.

Solution : Total 7 cards are in hand out of 52 cards in which,

2 hearts out of 13 hearts

2 diamonds out of 13 diamonds

2 clubs out of 13 clubs

1 spade out of 13 spades

As order doesn't matter,

Therefore the combination is

→

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

2/3

step-by-step explanation:

the slope of a line is equal to the rise/run. in this case the line rises 2 units for every +3 units it moves