Water is drained out of tank, shaped as an inverted right circular cone that has a radius of 4cm and a height of 16cm, at the rate of 2 cm3/min. at what rate is the depth of the water changing at the instant when the water in the tank is 8 cm deep? show all work and include units in your answer. give an exact answer showing all work and include units in your answer

cm³/min  

Step-by-step explanation:

Let h = height of water and r = radius of its surface  

At all times,  

So,  

We want

= -2 cm³/min  

When h = 8  cm

cm³/min

The depth of the water is decreasing at a rate of cm³/min

.

5x+2x=49

7x=49

x=7. 35 apples

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0