M∥n, m∠1 = 50°, m∠2 = 48°, and line s bisects ∠abc. what is m∠3?

Answer

m<3  = 49°

Step-by-step explanation:

It is given that,

M∥n, m∠1 = 50°, m∠2 = 48°, and line s bisects ∠ABC

m<DEF = m<1 + m<2 = 50° + 48° = 98°

Corresponding angle of <DEF is equal to <ABC = 98°

To find m<3

< 4 = <5 = 98/2 = 49° (Since line s bisects ∠ABC)

Therefore,

m<3 = 49°  (< 4 and <3 are vertically opposite angles)

m∠3 = 49°

Step-by-step explanation:

We are given that the angles m∠1 = 50° and m∠2 = 48° and the line s bisects ∠ABC.

If m∠1 = 50° and m∠2 = 48°, then ∠DEF = 50 + 48 = 98°

So ∠DEB will be equal to = 180 - 98 = 82°

If ∠DEB = 82°, then the angle from A to B will 180 - 82 = 98°.

We know that the line s bisects ∠ABC, therefore the measure of angle m∠3 will be half of 98 = 49°

won't that be plagrisim thought?

step-by-step explanation:

answer is b

step-by-step explanation: