What is the quotient (3x2 + 4x − 15) ÷ (x + 3)?

(3x-5)

Step-by-step explanation:

first we set it up x+3

we want to get rid of 3x^2 first so, x*3x= 3x^2

then we subtract x+3

distribute :3x*3=9x                 - (3x^2 +9x)

                                                   0 -5x

now we want to get rid of -5x, we use -5

-5(x+3)=-5x-15                x+3

                                                           -(-5x-15)

                                                                  0, so reminder of 0

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

12

step-by-step explanation:

12 + 5 = 17

12x2=24

24-7=17