Find the upper limit for the zeroes 2x^4-7x^3+4x^2+7x-6= 0 a. -1 b. 4 c. 5 explain!

x = 2 or x = 1 or x = -1 or x = 3/2   thus from the answers given only A: applies

Step-by-step explanation:

Solve for x over the real numbers:

2 x^4 - 7 x^3 + 4 x^2 + 7 x - 6 = 0

The left hand side factors into a product with four terms:

(x - 2) (x - 1) (x + 1) (2 x - 3) = 0

Split into four equations:

x - 2 = 0 or x - 1 = 0 or x + 1 = 0 or 2 x - 3 = 0

Add 2 to both sides:

x = 2 or x - 1 = 0 or x + 1 = 0 or 2 x - 3 = 0

Add 1 to both sides:

x = 2 or x = 1 or x + 1 = 0 or 2 x - 3 = 0

Subtract 1 from both sides:

x = 2 or x = 1 or x = -1 or 2 x - 3 = 0

Add 3 to both sides:

x = 2 or x = 1 or x = -1 or 2 x = 3

Divide both sides by 2:

 x = 2 or x = 1 or x = -1 or x = 3/2

the correct answer to your question is a. 4^4

good luck my friend!

hope this !

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step-by-step explanation:

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