Find the value of the polynomial: 6a^3–a^10+4a^3+a^10–8a^3+a for a=−3

-57

We can collect terms to simplify the arithmetic.

... = a^3(6 +4 -8) +a^10(-1 +1) +a

... = 2a^3 +a

... = a(2a^2 +1)

For a = -3, this is

... -3(2(-3)² +1) = -3(2·9 +1)

... = -3·19 = -57

8 2/3 is the answer

step-by-step explanation: just use a calculator

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?