In simplest radical form, what are the solutions to the quadratic equation 0 = –3x^2 – 4x + 5?

x = - ±

Step-by-step explanation:

given a quadratic equation in the form ax² + bx + c = 0

We can solve using the quadratic formula

with a = - 3, b= - 4 and c = 5

x = ( 4 ± ) / - 6

  = ( 4 ± ) / - 6

  = ( 4 ± ) / - 6

  = (4 ± 2) / - 6

  = - ±

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length