Two trains begin in milford and end in pinkerton, which is 300 miles away. train a leaves milford at 10: 00 a. m. and travels at a rate of 90 miles per hour. train b leaves milford at 8: 00 a. m. and travels at 70 miles per hour. which train(s) will arrive in pinkerton before 1: 00 p. m.?

Step-by-step explanation:

Alright, lets get started.

For train A:

Distance from Milford and Pinkerton is 300miles.

Speed of train A is 90 miles per hour.

So, time taken to complete this distance =

So, time taken to complete this distance =

Means train A will take 3.33 hours or say 3 hrs and 19.8 minutes to reach Pinkerton.

So,if it starts at 10:00 AM, then it will reach at 01 hrs 19.8 minutes PM (01:19.8 PM).

For train B:

Speed of train B is 70 miles per hour.

Train B will take time =

Means 4 hrs and 17.4 minutes.

So, if it starts at 8:00 Am, then it will reach at 12 hrs 17.4 minutes PM(12:17.4 PM).

So, train B will be reaching Pinkerton before 1:00 PM   :  Answer

Hope it will help :)

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m