Really need quadratic equation? a model rocket is launched with an initial upward velocity of 30 m/s. the rockets height h ( in meters) after t seconds is givenby the following. h=30t-5t^2 find all values of t for which the rockets height is 10 meters. round your answers to the nearest hundredth

t = 0.35, t = 5.65

Step-by-step explanation:

You are given h = 30t - 5t^2. Put this in standard form order (ax^2 + bx + c) by switching the two terms.

h = -5t^2 + 30t

Now you want to find all the values of t for which the rocket's height is 10 meters, so your equation will be equal to 10 instead of h, because 10 is the height you are solving for.

10 = -5t^2 + 30t

Make the entire equation equal to 0 by subtracting 10 from both sides.

0 = -5t^2 + 30t - 10

To solve this quadratic equation, the easiest way would be to use the quadratic formula:

Identify your a, b, and c values in the standard form equation (a = -5, b = 30, c = -10) and substitute these values into the quadratic formula.

We have (-30 ± sqrt 700)/-10.

Use a calculator to input the two solutions and solve for them; (-30 + sqrt 700)/-10 and (-30 - sqrt 700)/-10.

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)