Ijust need with number 17 when it comes to writing out the equation

equations

solution

a. It usually works well to let a variable represent the quantity the problem statement is asking you to find. I like to choose variable names that help me remember what the variable stands for. (x and y rarely do that) So, let's choose "a" for the cost of an adult ticket, and "s" for the cost of a student ticket.

The equations express the relationships described by the problem statement. The first relationship expresses the total revenue in terms of the numbers of tickets sold. You know that multiplying the number of tickets by the cost of the ticket will give the revenue from sales of that ticket. So, the total revenue is ...

... 64a +132s = 1040

The problem statement also tells you the relationship between the costs. An adult ticket is twice the cost of a student ticket, so ...

... a = 2s

These equations are your system of linear equations.

b. The solution can be found using substitution. Since the second equation gives an expression for "a", we can use that in the first equation.

... 64(2s) +132s = 1040

... 260s = 1040 . . . . . . . . simplify

... 1040/260 = s = 4

... a = 2s = 2·4 = 8

An adult ticket costs $8; a student ticket costs $4.

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

da freeck kinda math is this just drop out

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