Which best describes your ability to write a linear equation in standard point slope and slope intercept form

There are many ways to describe a linear equation:

standard form: Ax + By = C, where x-intercept point is C/A and y-intercept point is C/B

point slope form: y - y1 = m(x - x1), where m is the slope of the line and (x1, y1) is a point on the line

slope intercept form: y = mx + b, where m is the slope and b is the y-intercept

All of them can describe any linear equation,  which is best depends on what data you have. For example if you have the interceptions with the axis, use the standard form; if you have any two points (x2, y2) and (x3, y3), compute the slope as: m = (y3 -y2)/(x3 - x2) and use the point slope form. And always you can transform one form into another one; continuing with the last example, if you have the point slope form, you can isolate y as: y = mx - mx1 + y1, to get  the slope intercept form (b = - mx1 + y1).

19

step-by-step explanation:

system of linear equation

step-by-step explanation:

as given in the data

a= 20 , b= -12

let us suppose that it is a straight line equation

now we know the formula for the system of linear equation

b= ma + c )

here m is slope of a straight line which is equal to formula

m=   (ii)

and here c is a constant

now putting the value of a and b in equation (ii)

m=

m=

putting the value of a,b and m in equation (i) gives us

-12 = + c

-12=-12 + c

adding 12 to both sides

-12 +12 = -12 +12 +c

0 =c

or c=0

as the value of the constant is zero which gives us that it is a linear equation and this order pair satisfies the system of linear equations.