What is a quartic function with only the two real zeros given? x = –4 and x = –1 question options: y = x4 + 5x3 + 5x2 + 5x + 4 y = x4 + 5x3 + 5x2 + 5x – 5 y = -x4 + 5x3 + 5x2 + 5x + 4 y = x4 - 5x3 - 5x2 - 5x - 4

y = x^4 + 5x^3 + 5x^2 + 5x + 4

Step-by-step explanation:

Each of the latter three answers demonstrates one change of sign in its coefficients. According to Descarte's Rule of Signs, that means each of them has one positive real root. If there is a positive real root, the only two real roots will not be -4 and -1 (both negative).

The only viable option is the first one.

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There are other ways you can go at this. I like to let a graphing calculator show the zeros of functions of higher degree. Only the first function has only the two real roots given.

You can also evaluate each function or do synthetic division to see which polynomial has -1 or -4 as a root. Shown in the second attachment is the first function evaluated for x=-1.

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval