What is the equation of a line with a slope of 7 and a point (1, 8) on the line? express the equation in the form of y = mx + b, where m is the slope and b is the y-intercept. enter your answer in the box.

y = 7x + 1

Step-by-step explanation:

If the slope and coordinates have already been given, you can plug the values into the following equation of a line:

y - y1 = m(x - x1)

Where y1 is the y coordinate, so in this case 8,

x1 is the x coordinate which is 1

m is the slope, so 7:

y - 8 = 7(x - 1)

Expand the brackets:

y - 8 = 7x - 7

To isolate the y, we need to move the -8 over to the other side making it a positive 8:

y = 7x - 7 + 8

y = 7x + 1

So the equation of the line is y = 7x + 1

2

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