Write the first five terms of the sequence in which the nth term is

C) 2,6,24,120,720

Step-by-step explanation:

Here the n-th term An =

A1 is the first term

A1 = (1 + 2)!/(1 + 2)

= 3!/3

A1 = 2

A2 is the second term

A2 = (2 +2)!/(2 +2)

= 4!/4

A2 = (1*2*3*4) /4

A2 = 6

A3 is the third term

A3 = (3 + 2)!/(3 +2)

A3 = 5!/5

A3 = 24

A4 is the fourth term

A4 = (4 + 2)!/(4 + 2)

A4 = 6!/6

A4 = 120

A5 is the fifth term

A5 = (5 + 2)!/(5 +2)

A5 = 7!/7

A5 = 720

C) 2,6,24,120,720

Thank you.

yes. we do proportions in probabilities.

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all