What are three consecutive integers whoose sum of 138? write and solve an equation with one variable.

Consecutive integers are 1 more than the other.

If one of them is x.

The three would be x, x + 1, x + 2

Since the sum are 138

x + (x + 1) + (x +2) = 138

x + x + 1 + x +2 = 138

x + x + x + 1 + 2 = 138

3x + 3 = 138

3x = 138 - 3

3x = 135

x = 135/3

x = 47.

So the numbers are, x, x + 1, x + 2, = 47,  47 + 1 = 48, 47 + 2 = 49

The integers are 47, 48, and 49.

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The first option would be correct if it were one half and not one