20 ptsa. a transformation maps zowe onto lfma. does the transformation appear to be an isometry? explain. b. what is the image of ze? z e bar , question mark what is the preimage of m?

1. No

2. The image of ZE is LA, the preimage of point M is point W

Step-by-step explanation:

This transformation maps quadrilateral ZOWE onto quadrilateral LFMA.

1. An isometry is a tansformation that preserves lengths. This transformation is not isometry, because lengths of quadrilatrel LFVA sides are greater than lengths of quadrilateral ZOWE sides.

2. This transformation is a dilation by a factor greater than 1 about some center of dilation. The image of ZE is LA (the image of ZO is LF, of OW - FM, EW - AM). Thus, the preimage of point M is point W.

asnwer is (g o h o f)(x) = 2x - 6/x + 7

step-by-step explanation:

given,

f(x) = x - 3/x

g(x) = x + 3

h(x) = 2x + 1

we need to find : (g o h o f)(x)

we can write (g o h o f)(x) = g[ h{ f(x) } ]

so first we find h{f(x)}

h{f(x)} = f(x) + 3 = (x - 3/x) + 3

h{f(x)} = x - 3/x + 3

now we find g[ h{ f(x) } ].

g[ h{ f(x) } ] = g(x - 3/x + 3)       {plug h{f(x)} = x - 3/x + 3 in g[h{f(x)}] }

g(x - 3/x + 3) = 2 (x - 3/x + 3) + 1

                    = 2x - 6/x + 6 + 1

                    = 2x - 6/x + 7

hence we get (g o h o f)(x) = 2x - 6/x + 7