Find the sale price of each item. round to two decimal places when necessary. 8. original price: $45.00; markdown: 22% 9. original price: $89.00; markdown: 33% 10. original price: $23.99; markdown: 44% 11. original price: $279.99, markdown: 75% eh, might aswell do the last question too. sorry! : ) 12. how can you determine the sale price if you are given the regular price and the percent of markdown?

8) Sale price : 45* (100%-22%)= 45* 78/100= 35,1 $

9) 89* ( 100%-33%)= 89*67/100=59,63 $

10) 23,99* (100%-44%)= 13,43 $

11) 279,99*25/100= 69,99 $

12) Sell price= regular price* ( 100%- Markdown)

Step-by-step explanation:

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v