Bess is trying to solve a puzzle where she has to figure out two numbers, x and y. the sum of twice x and 3 times y is less than 6. also, y must be greater than 1 less than twice the x. which graph represents the possible solutions? graph the inequalities 2 x plus 3 y less than 6 and y greater than 2 x minus 1 graph the inequalities 2 x minus 3 y less than 6 and y greater than 2 x minus 1 graph the inequalities 3 x minus 2 y less than 6 and y greater than 3 x minus 2 graph the inequalities 3 x minus 5 y less than 6 and y greater than 3 x plus 2

The correct option is 1.

Step-by-step explanation:

Let the two  numbers are x and y.

Condition 1: The sum of twice x and 3 times y is less than 6.

                            ..... (1)

Condition 2: y must be greater than 1 less than twice the x.

                              .... (2)

Therefore the graph of inequality (1) and (2) represent the all possible solutions.

Option 1 is correct. The graph of above inequality are shown below.

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !

given the equation is 8+9z=-6, the first step would be to subtract the 8 from both sides:

8+9z-8=-6-8

since 8 minus 8 = 0, this would cancel out the 8. and since -6 minus 8 equals -14, the equation would look like this

9z = -14