3.25+0.5x+1 1/3 + 5/6 x=5 11/12 what is x? plz due soon

x= 1

Step-by-step explanation:

Convert 5\frac{11}{12}5

12

11

 to improper fraction. Use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

c

b

=

c

ac+b

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{5\times 12+11}{12}3.25+0.5x+1

3

1

+

6

5

x=

12

5×12+11

2 Simplify 5\times 125×12 to 6060

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{60+11}{12}3.25+0.5x+1

3

1

+

6

5

x=

12

60+11

3 Simplify 60+1160+11 to 7171

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{71}{12}3.25+0.5x+1

3

1

+

6

5

x=

12

71

4 Simplify \frac{5}{6}x

6

5

x to \frac{5x}{6}

6

5x

3.25+0.5x+1\frac{1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+1

3

1

+

6

5x

=

12

71

5 Convert 1\frac{1}{3}1

3

1

 to improper fraction. Use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

c

b

=

c

ac+b

3.25+0.5x+\frac{1\times 3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

3

1×3+1

+

6

5x

=

12

71

6 Simplify 1\times 31×3 to 33

3.25+0.5x+\frac{3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

3

3+1

+

6

5x

=

12

71

7 Simplify 3+13+1 to 44

3.25+0.5x+\frac{4}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

3

4

+

6

5x

=

12

71

8 Simplify 3.25+0.5x+\frac{4}{3}+\frac{5x}{6}3.25+0.5x+

3

4

+

6

5x

 to \frac{13.75}{3}+\frac{4x}{3}

3

13.75

+

3

4x

\frac{13.75}{3}+\frac{4x}{3}=\frac{71}{12}

3

13.75

+

3

4x

=

12

71

9 Simplify \frac{13.75}{3}

3

13.75

 to 4.5833334.583333

4.583333+\frac{4x}{3}=\frac{71}{12}4.583333+

3

4x

=

12

71

10 Subtract 4.5833334.583333 from both sides

\frac{4x}{3}=\frac{71}{12}-4.583333

3

4x

=

12

71

−4.583333

11 Simplify \frac{71}{12}-4.583333

12

71

−4.583333 to \frac{4}{3}

3

4

\frac{4x}{3}=\frac{4}{3}

3

4x

=

3

4

12 Multiply both sides by 33

4x=\frac{4}{3}\times 34x=

3

4

×3

13 Simplify \frac{4}{3}\times 3

3

4

×3 to \frac{12}{3}

3

12

4x=\frac{12}{3}4x=

3

12

14 Simplify \frac{12}{3}

3

12

 to 44

4x=44x=4

15 Divide both sides by 44

x=1

your mom x 3

step-by-step explanation:

step-by-step explanation:

no of data

divide by no of mode