The following table gives results from two groups of students who took a nonproctored test. use a 0.01 significance level to test the claim that the samples are from populations with the same mean. group 1: n=30 mean=70.29 s=22.09 group 2: n=32 mean=74.26 s=18.15 original claim: opposite claim: alternative and null hypotheses: significance level: test statistic: p-value: reject or fail to reject: final conclusion:

Original claim is

Opposite claim is

Null and alternative hypotheses:

Significance level: 0.01

Test statistic:

We can use TI-84 calculator to find the test statistic and P-value. The steps are as follows:

Press STAT and the scroll right to TESTS

Scroll down to 2-SampTTest... and scroll to stats.

Enter below information.

Pooled: Yes

Calculate.

The output is in the attachment.

Therefore, the test statistic is:

P-value: 0.4412

Reject or fail to reject: Fail to reject

Final Conclusion: Since the p-value is greater than the significance level, we, therefore, fail to reject the null hypothesis and conclude that the there is sufficient evidence to support the claim that the samples are from populations with the same mean.

step-by-step explanation:

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation: