The midpoint of jk is point l at (–1, 8). one endpoint is j(4, –15). which equations can be solved to determine the coordinates of the other endpoint, k? check all that apply. = –1 = 4 –15 + y1 = 4 –15 + y1 = 16 = x1 = y1

-2 = 4+x2

16 = -15 + y2

Step-by-step explanation:

xm, ym = (x1+x2)/2 , (y1+y2)/2

xm = (x1+x2)/2

ym =  (y1+y2)/2

substitute in what we know

-1 = (4+x2)/2

8 =  (-15+y2)/2

multiply each equation by 2

-2 = 4+x2

16 = -15 + y2

what's that

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.