Which equations have no real solution but have two complex solutions?

equations have no real solution but have two complex solutions When  discriminant is negative.

Step-by-step explanation:

The quadratic equation ha 2 solution

let a, b and c are the coefficients of equation.

These 2 solutions are based on the value of discriminant,

discriminant = square root (b^2 - 4ac)

If b^2 - 4ac  is a negative value we cannot find its root.

The square root of a negative number is complex number.

Therefore equations have no real solution but have two complex solutions

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this

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step-by-step explanation: