If z=-1-sq root 3i and z^6=a+bi then a = and b=

a=64  and b=0

Step-by-step explanation:

use

Now we find out x using given z

Multiply and divide the right side by -2

We know cos(pi/3) = 1/2

sin(pi/3)= sqrt(3)/2

compare the above equation with use

x= pi/3

so

Plug in 2pi in the z equation

So z= 64(1 + i(0))

z=64

So a= 64  and b=0

range =5

step-by-step explanation:

to find the range, we take the largest value and subtract the smallest value.

the largest value is 5

the smallest value is 0

the range is 5-0   =5