Larry is considering taking out a loan. he estimates that he can afford monthly payments of $265 for 10 years in order to support his loan. he finds that with an apr 5.5 compounded monthly he can take a loan of $24,418.05 assuming that larry’s monthly payment and the length of the loan remain fixed which of these statements is true about the size of the loan larry could take if he received a different apr?

D

Step-by-step explanation:

the guy above explained

option-C

option-D

Step-by-step explanation:

we are given

He estimates that he can afford monthly payments of $265 for 10 years in order to support his loan

so, firstly we will find total amount

now, we can verify each options

option-A:

r=6.6% =0.066

Amount is same

now, we can use APR formula

It is compounded monthly

so, n=12

we can plug it and then we can solve for P

we can see that it is less than 24418.05

So, this is FALSE

option-B:

r=6.2% =0.062

Amount is same

now, we can use APR formula

It is compounded monthly

so, n=12

we can plug it and then we can solve for P

we can see that it is less than 24418.05

So, this is FALSE

option-C:

r=5.2% =0.052

Amount is same

now, we can use APR formula

It is compounded monthly

so, n=12

we can plug it and then we can solve for P

we can see that it is less than 24418.05

So, this is TRUE

option-D:

r=5.8% =0.058

Amount is same

now, we can use APR formula

It is compounded monthly

so, n=12

we can plug it and then we can solve for P

we can see that it is less than 24418.05

So, this is TRUE

perimeter of the first rectangular board is 9 feet.

step-by-step explanation:

let p = perimeter of first board.

l = length of first board

w = width of first board

length of first board = 2 * width of first board - 3

l = 2w - 3

perimeter of first board = 2l + 2w

since l = 2w-3, then

p = 2*(2w-3) + 2w which equals 4w-6 + 2w which equals 6w-6

length and width of the second board are reciprocals of corresponding length and width of the first board.

length of second board = 1/(2w-3)

width of second board = 1/w

perimeter of second board is 1/5th perimeter of the first board.

perimeter of second board = p/5

perimeter of the second board = (2/(2w-3) + 2/w)

since the perimeter of the first board is 5 times the perimeter of the second board, this means that:

6w-6 = 5*(2/(2w-3) + 2/w)

which is the same as:

6w-6 = (10/(2w-3) + 10/w)

if we multiply both sides of this equation by (2w-3), we get:

(6w-6)*(2w-3) = 10 + 10*(2w-3)/w

if we multiply both sides of this equation by w, we get:

(6w-6)*(2w-3)*w = 10*w + 10*(2w-3)

we can simplify this to become:

(6w-6)*(2w-3)*w = 10w + 20w - 30

which becomes:

(6w-6)*(2w-3)*w = 30w-30

if we divide both sides of this equation by (6w-6), we get:

(2w-3)*w = (30w-30)/(6w-6)

which becomes:

(2w-3)*w = 5

this can be simplified to:

2w^2 - 3w = 5

subtract 5 from both sides of this equation to get:

2w^2 - 3w - 5 = 0

which can be factored into:

(2w-5)*(w+1) = 0

which makes:

w = 5/2

or

w = -1.

w can't be negative so the only possible answer is w = 5/2.

if w = 5/2, then

p = 2w-3 = 5-3 = 2

we have:

p = 2

w = 5/2

p = 2l + 2w gets p = 4 + 5 = 9

the perimeter of the first board is 9 feet.

since the perimeter of the second board is 1/5 the perimeter of the first board, the perimeter of the second board is 9/5.

to see if that's correct, we substitute known values for l and w into the second board.

the length of the second board is 1/l.

this becomes 1/2.

the width of the second board is 1/w

this bgecomes 1/(5/2) = (2/5)

let l2 = length of second board.

let w2 = width of second board.

l2 = (1/2)

w2 = (2/5)

let p2= perimeter of second board.

then p2 = 9/5

since p2 = 2*l2 + 2*w2, we should get p2 = 9/5 using the dimensions of l2 and w2.

2 * l2 = 2 * (1/2) = 1

2 * w2 = 2 * (2/5) = 4/5

1 is the same as 5/5

5/5 + 4/5 = 9/5

p2 checks out good.

the dimensions as given are good.

answer to the problem is:

perimeter of the first rectangular board is 9 feet.

oof cheaters cheat because they’re lazy that’s why i cheat xd

: )

step-by-step explanation: