The test scores for 10 students in ms. sampson’s homeroom were 61, 67, 81, 83, 87, 88, 89, 90, 98, and 100. create a frequency table with the intervals 61-70, 71-80, 81-90, 91-100

The required frequency table,

Class Interval:     61 - 70          71 - 80            81 - 90          91 - 100

Frequency:            2                     0                      6                    2

Step-by-step explanation:

Here, test scores for 10 students are,

61, 67, 81, 83, 87, 88, 89, 90, 98, and 100.

Since, In interval  61 - 70, scores are 61 and 67.

Therefore, frequency of interval 61 - 70 = 2

In interval 71 - 80, there are no scores.

Therefore frequency of interval 71 - 80 = 0

In Interval 81 - 90, scores are , 81, 83, 87, 88, 89 and 90.

Therefore  frequency of interval 81 - 90 = 6

In Interval 91 - 100, scores are 98 and 100.

Therefore, frequency of interval 91 - 100 = 2

50- 250 is correct i did that one too

step-by-step explanation:

the revenue of the fitness center, y, is the product of two factors: the number of members and the fee paid by each member. there are 320 members now, but number of members goes down by 10 for each $5 increase in fees, so if x is the number of $5 price increases then members is equal to (320 - 10x). since the fee is currently $45, and the fee increases by $5 for every price bump x, the fee is given by (45 + 5x). so, revenue y is given by y = (320 - 10x)(45 + 5x).