For which values of x is the inequality 3(1 + x) > x + 17 true?

x>7

Step-by-step explanation:

3(1 + x) > x + 17

distribute

3 + 3x> x+17

subtract x from each side

3 +3x-x > x-x+17

3+2x > 17

subtract 3 from each side

3-3+2x > 17-3

2x>14

divide by 2

2x/2 > 14/2

x>7

2018

Step-by-step explanation:

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph