Geometry problems with inequalities in one triangle

1. ∠1 is the sum of ∠2 and another non-zero angle, so must be greater than ∠2.

2. ∠1 is the sum of ∠2 and another non-zero angle, so must be greater than ∠2.

Step-by-step explanation:

1. ∠1 is an external angle to the triangle, so is the sum of the measures of the opposite internal angles. That is, ...

... ∠1 = ∠2 + ∠3

If we say ∠3 > 0, then we can rewrite the above equation as ...

... ∠3 = ∠1 - ∠2

Substituting into ...

... ∠3 > 0

we have ...

... ∠1 - ∠2 > 0

Adding ∠2 gives ...

... ∠1 > ∠2

2. ∠1 = ∠2 + ∠4, because both ∠1 and the angle sum are opposite interior angles where a transversal crosses parallel lines. By the same logic used above (replacing ∠3 with ∠4 in the development), ...

... ∠1 > ∠2

i saw this question before, dont know the asnwer srry

step-by-step explanation: