On average 1 1/3 bushels od seed are needed to plant 1 arce of wheat. how many bushels of seed would be required to pay it arces?

4/3 x 30/1=120/3

120/3=40

40 bushels of seed would be needed to plant 30 acres of wheat.

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube