Consider the radical equation square root of n+4 = n – 2. which statement is true about the solutions n = 5 and n = 0? a. the solution n = 5 is an extraneous solution. b. both n = 5 and n = 0 are true solutions. c. the solution n = 0 is an extraneous solution. d. neither are true solutions to the equation.

it's not D i took the test and got it wrong

C.The solution n = 0 is an extraneous solution.

Step-by-step explanation:

The given equation is

Squaring both sides we have:

Expanding the right side:

Or ,

n(n-5)=0

n=0 or n=5.

Checking the solution for n=0 in the above equation:

False .

For n=5.

True.

C.The solution n = 0 is an extraneous solution.

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

e

step-by-step explanation:

an equation by definition has to have two or more variables (x and 2 in this case)