East high schools student council plans to buy some stools and chairs for a new student center. they need to buy 25 more chairs than stools. the chairs cost $32 each and the stools cost $28 each. if the budget is $2,620, how many chairs can they buy?

The number of chairs they buy is,  55

Step-by-step explanation:

Let x be the number of stools buy and y be the number of chairs buy.

As per the given condition : East high school need to buy 25 more chairs than stools.

i.e,

y = x +25            ......[1]

It is given that the chairs cost $32 each and the stools cost $ 28 each and the total budget is $ 2,620 then;

28x+32y = 2620           ......[2]

Substitute equation [1] into [2] we have:

using distributive property:  

Combine like terms:

Subtract 800 from both sides we have:

Simplify:

Divide both sides by 60 we have:

Simplify:

x = 30.3333...

Since , the stools they buy are are in number so we have , x = 30 stools.

Substitute in equation [1] we have;

y = 30 + 25 = 55

Therefore, the number of chairs they buy is, 55 chairs.

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.