Which transformations could be performed to show that △abc is similar to △a"b"c"? a reflection over the x-axis, then a dilation by a scale factor of 3 b reflection over the x-axis, c then a dilation by a scale factor of a 180° rotation about the origin, d then a dilation by a scale factor of 3 a 180° rotation about the origin, then a dilation by a scale factor of

The similarity of triangles ABC and A'B'C' is performed by rotating one triangle about the origin at . Hence, option (D) is correct.

As per the given problem, the triangle is ABC is an original geometry. And triangle A'B'C' is an reference geometry .

This shows that C is rotated 180 degrees about origin to get the new coordinates as (0, -3) and then new coordinates were dilated by 1/3 which forms C' as (0, -1)

Thus, we can conclude that the similarity of triangles ABC and A'B'C' is performed by rotating one triangle about the origin at . Hence, option (D) is correct.

Learn more about scale factor and dilation here:

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Option D.

Step-by-step explanation:

If two triangles ΔABC and ΔA'B'C' are similar then we take point C of ΔABC to find the transformation performed form C to C'.

Coordinates of C are (0, 3) and the coordinates of C' are (0, -1).

This shows that C is rotated 180° about origin to get the new coordinates as (0, -3) and then new coordinates were dilated by 1/3 which forms C' as (0, -1)

Therefore option D is the correct option.

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