Write the equation in slope-intercept form that contains the following point with the given slope. slope= 2 ; (-3, 1)

y = 2x+7

Step-by-step explanation:

we need to start with point slope form

y-y1 = m(x-x1)

y-1 = 2 (x--3)

y-1 = 2(x+3)

distribute

y-1 = 2x+6

add 1 to each side

y-1+1 = 2x+6+1

y = 2x+7

this is in slope intercept form (y=mx+b)

the slope is 2 and the y intercept is 7

y = 2x + 7

Step-by-step explanation:

Slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept (hence the name slope-intercept form).

You are given the slope and a point that the line goes through, so the best equation for a line to use is the point-slope form (why? because the name says POINT-SLOPE so that means if you have a point and a slope then this would be the ideal equation).

Point-slope form is y - y1 = m(x - x1). In this form you will be plugging the x and y coordinates of the point into y1 and x1, and plugging the slope in for m.

Substitute in the given slope and point into the point-slope form.

y - y1 = m(x - x1) ⇒ y - (1) = 2(x - (-3))

Take away the parentheses and simplify.

y - 1 = 2(x + 3) ⇒ y - 1 = 2x + 6

Add 1 to both sides of the equation.

y = 2x + 7 is your answer in slope-intercept form (y = mx + b).

the image is given below

since the options are not given so we draw it from the equation

the given equation is

y = (x-1) (x+4)

y = y² + 3x - 4

the above equation is a quadratic equation which will have two roots. if we draw the graph for it, it will look like this