The length of a rectangle is 2 feet more than 5 its width. the perimeter is 52 feet. find the dimension of the rectangle

The length is 22 feet. The width is 4 feet.

Step-by-step explanation: Create an equation for the length: 2+5w=52.

Now combine the two sides to get 4+10w=52. Plug in some numbers that seem reasonable. I started with 4, checked my work and found that it was right. This problem is all about trial and error.

So, 4+10(4)= 44. Make sure to remember the width, so add 4 for each side: 44+8. 44+8=52. Hope this helps :)

W= 4

L= 22

Step-by-step explanation:

1. L= 2+ 5w

W = W

2. 52= 2(L) + 2(W)

= 10 W + 4 + 2W

= 12W + 4

3. 52-4= 12 W

48 = 12W

4= W

4. L = 5W + 2

= 5 (4) +2

= 22

actually your concept is wrong

step-by-step explanation:

150% of x =300

150x=300×100

x=(300×100)÷150

x=200