Median am and cn of △abc intersect at point o. what part of area of △abc is the area of △aon?

The area of △AON is th part of the area of △ABC.

Step-by-step explanation:

It is given that AM and CN are medians. The intersection point of medians is centroid. Median divides the triangle is two equal parts.

The centroid divides each median in a ratio of 2:1.

Therefore CO:ON is 2:1.

Let the area of △ABC be x.

Since CN is median therefore the area of triangle ANC and BNC are same and half of the total area of the triangle ABC.

Area of triangle ANC is .

The point O divide the median CN is 2:1. So the line AO divides the area in 2:1.

Area of triangle AON is rd of area of ANC. Area of AON is

The area of ABC is x and the area of AON is .

Therefore the area of △AON is th part of the area of △ABC.

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step-by-step explanation:

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is