50 will give ! a person standing at the top of mountain everest would be approximately 5.5 mi high. the radius of earth is 3959 mi. what is the distance to the horizon from this point? enter your answer as a decimal in the box. round only your final answer to the nearest tenth. plz show !

208.8 mi

Step-by-step explanation:

Form a triangle with the centre of the Earth (C) at one point, the horizon (H) as a second point, and the top of Mt. Everest (O) as the third (see diagram).

Let

r  = Earth’s radius

h = height of Mt Everest

d = distance to horizon

∆CHO is a right triangle.

               d² + r² = (r+h)²

       d² + 3959² = (3959+5.5)²

d² + 15 673 681 = 3964.5²

d² + 15 673 681 = 15 717 260     Subtract 15 673 681 from each side

                     d² = 43 579             Take the square root of each side

                      d = 208.8 mi

The distance from the top of Mt Everest to the horizon is 208.8 mi.

the answer is c)8

step-by-step explanaction:

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: