Points m and n are the midpoints of sides ac and bc of △abc. prove that the ratio of the area of △mnc to the area of abnm is 1: 3.

Step-by-step explanation:

If points M and N are the midpoints of sides AC and BC of △ABC, then segment MN is a midline segment of the triangle ABC. By the triangle midline theorem, MN║AB and is half of AB.

Since

then triangles ABC and MNC are similar by AAA theorem with factor of similarity. Thus,

The area of the quadrilateral ABNM is

Then

the answer is somewhere there guys it really . there im just not gonna answer

step-by-step explanation:

but i'm guessing ur first option tho