What is the missing constant term in the perfect square that starts with x^2-12x

Essentially, we are trying to find the missing constant term of (remember that we are subtracting due to the negative sign in front of the second term). Let's expand this to see what we can work with:

Now, we know the second term is , so let's set the second term in the polynomial we just found equal to :

We have found . We know the missing constant term is , according to the polynomial we found earlier. Thus, the missing term is:

The missing constant term is 36.

the answer would be c:   ax + b = ax + c

step-by-step explanation:

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)