What is the equation of a line that passes through the point (0, 8) and is parallel to a line with a slope of 4/5 ?

y = 4/5 x +8

Step-by-step explanation:

point slope form of a line is

y-y1 = m(x-x1)

m = 4/5  (since it is parallel is has the same slope)

point (0,8)

y-8 = 4/5(x-0)

y-8 = 4/5 x

add 8 to each side

y = 4/5 x +8

this is now in slope intercept form

the y intercept is 8

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

you can use a^2+ b^2=c^2