Mathematics, 30.06.2019 01:30 jbot9050
Will make ! factor using the identity: a3 + b3 = (a + b)(a2 – ab + b2) 8z3 + 27 a.(2z + 3)(z2 – 6z + 9) b.(2z + 3)3 c.(8z3 + 27)(8z2 – 16z3 + 729) d.(2z + 3)(4z2 – 6z + 9)
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Will make ! factor using the identity: a3 + b3 = (a + b)(a2 – ab + b2) 8z3 + 27 a.(2z + 3)(z2 – 6z...
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