Atelephone company offers two plans with per-minute charges. plan a involves a monthly rental of $12, and call charges at 7¢ per minute. plan b involves a monthly rental of $15, and call charges at 5¢ per minute.
write an inequality in terms of the number of minutes which shows when plan a is less expensive than plan b. solve the inequality, showing the steps in your work.

Step-by-step explanation:

Let x be the no. of minutes

Plan A

Monthly rental = $12

Call charges for 1 minute =  7¢

1 cents = 0.01 dollars

So, Call charges for 1 minute =  $0.07

Call charges for x minutes = 0.07 x

Total cost of Plan A = 12+0.07x

Plan B

Monthly rental = $15

Call charges for 1 minute =  5¢

1 cents = 0.01 dollars

So, Call charges for 1 minute =  $0.05

Call charges for x minutes = 0.05 x

Total cost of Plan B = 15+0.05x

An inequality in terms of the number of minutes which shows when Plan A is less expensive than Plan B=

Solving the inequality :

So, the no. of minutes must be less than 150 for  Plan A to be less expensive than Plan B

Hence an inequality in terms of the number of minutes which shows when Plan A is less expensive than Plan B is