List the first five terms of the sequence

a1= 3/2

a2=9/5

a3=27/10

a4=81/17

a5=243/26

Step-by-step explanation:

Fisrt: an = a1

Formula = (3^n)/(n^2+1)

Replace n by 1 and then continue for a2, a3, a4, a5

Therefore:

a1=(3^1)/(1^2+1) = 3/(1*1+1) = 3/(1+1) = 3/2

a2=(3^2)/(2^2+1) = 9/(4+1) = 9/5

a3 = (3^3)/(3^2+1) = 27/(9+1) = 27/10

a4 = (3^4)/(4^2+1) = 81/(16+1) = 81/17

a5 = (3^5)/(5^2+1) = 243/(25+1) = 243/26

1.4

2.3

step-by-step explanation:

the formula for the constant of variation is

y= kx

divide each side by x

y/x =kx/x

y/x =k

we know a and y

1.   y/x = k

4/1 =4

check the other values to make sure they are the same

8/2 = 4   12/3 =4   and 16/4 =4  

the constant of variation is 4

2.   y/x = k

3/1 =3

check the other values to make sure they are the same

6/2 = 3   9/3 =3   and 12/4 =3  

the constant of variation is 3