Aparticle is moving along the x-axis so that its position at t ≥ 0 is given by s(t)=(t)ln(5t). find the acceleration of the particle when the velocity is first zero 5e 5e^2 e none of these

Step-by-step explanation:

we are given equation for position function as

Since, we have to find acceleration

For finding acceleration , we will find second derivative

now, we can find derivative again

Firstly, we will set velocity =0

and then we can solve for t

we get

now, we can plug that into acceleration

and we get

answer is c

step-by-step explanation:

81/12=324/x

x=48